| Main Archive Page > Month Archives > wireshark-dev archives |
Re: [Wireshark-dev] IPv6 longest representation vs INET6_ADDRSTRLEN
From: Jakub Zawadzki <darkjames-ws_at_nospam>Date: Thu May 05 2011 - 13:01:20 GMT
To: wireshark-dev@wireshark.org
On Thu, May 05, 2011 at 02:01:06PM +0200, Jakub Zawadzki wrote:
> IMHO when IPv4-mapping is used the longest address is:
> ::ffff:255.255.255.255 (22B)
>
> Anyone knows inet_ntop(AF_INET6, ..) implementation which can actually use 46 bytes?
Maybe some inet_ntop() implementation don't generate short addresses? (0000 instead of ::)
so ipv4 mapped address would be: "0000:0000:0000:0000:0000:0000:255.255.255.255"
I think I'll just copy inet_ntop6() from wsutil/inet_ntop.c to address_to_str.c...
___________________________________________________________________________
Sent via: Wireshark-dev mailing list <wireshark-dev@wireshark.org>
Archives: http://www.wireshark.org/lists/wireshark-dev
Unsubscribe: https://wireshark.org/mailman/options/wireshark-dev
mailto:wireshark-dev-request@wireshark.org?subject=unsubscribe